(1/6)^(3*x+2)*216^(3*x)=(1/216)

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Solution for (1/6)^(3*x+2)*216^(3*x)=(1/216) equation: 



(1/6)^(3x+2)*216^(3x)=(1/216)

We move all terms to the left:

(1/6)^(3x+2)*216^(3x)-((1/216))=0



Domain of the equation: 6)^(3x+2)*216^3x!=0

x∈R



We add all the numbers together, and all the variables

(+1/6)^(3x+2)*216^3x-((+1/216))=0

We calculate fractions


()/6^(3x+2)*216^3x*216)))+(-(6^(3x+2)*216^3x)/6^(3x+2)*216^3x*216)))=0

We calculate fractions


(()*6^(3x+2)*216^3x*216))))/(6^(3x+2)*216^3x*216)))+(-(6^(3x*6^(3x+2)*216^3x*216))))+2*216^3x)*6^(3x+2)*216^3x*216)))+(-(6^3x/(6^(3x+2)*216^3x*216)))+(-(6^(3x*6^(3x+2)*216^3x*216))))=0



We calculate terms in parentheses: +(()*6^(3x+2)*216^3x*216))))/(6^(3x+2)*216^3x*216)))+(-(6^(3x*6^(3x+2)*216^3x*216))))+2*216^3x)*6^(3x+2)*216^3x*216)))+(-(6^3x/(6^(3x+2)*216^3x*216)))+(-(6^(3x*6^(3x+2)*216^3x*216)))), so:

()*6^(3x+2)*216^3x*216))))/(6^(3x+2)*216^3x*216)))+(-(6^(3x*6^(3x+2)*216^3x*216))))+2*216^3x)*6^(3x+2)*216^3x*216)))+(-(6^3x/(6^(3x+2)*216^3x*216)))+(-(6^(3x*6^(3x+2)*216^3x*216)))

We can not solve this equation

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